Jawapan Buku Teks Fizik Tingkatan 4 Kssm Aktiviti 13 Work Work Apr 2026
In this guide, we will explore the concept of work, energy, and efficiency in the context of physics. Specifically, we will focus on Aktiviti 13 in the Buku Teks Fizik Tingkatan 4 KSSM (Kurikulum Standard Sekolah Menengah) textbook. This activity aims to help students understand the relationship between force, displacement, and work done, as well as the concepts of kinetic energy, potential energy, and efficiency.
KE = ½ × m × v^2 = ½ × 5 kg × (2 m/s)^2 = 10 J
Then, calculate the efficiency:
Then, calculate the efficiency:
A 5 kg object is moving at a velocity of 2 m/s. Calculate its kinetic energy.
W = F × s = 20 N × 3 m = 60 J
A machine lifts a 100 kg load to a height of 5 m in 10 seconds. If the machine requires an input energy of 5000 J, calculate its efficiency. In this guide, we will explore the concept
Gravitational potential energy is the energy an object possesses due to its height above the ground. The gravitational potential energy (GPE) of an object is given by the equation:
Work done = m × g × h = 100 kg × 9.8 m/s^2 × 5 m = 4900 J
Work done = m × g × h = 50 kg × 9.8 m/s^2 × 2 m = 980 J KE = ½ × m × v^2 =
GPE = m × g × h = 10 kg × 9.8 m/s^2 × 4 m = 392 J
Solution:
where m is the mass of the object and v is its velocity. If the machine requires an input energy of
Now, let's apply the concepts we've learned to Aktiviti 13 in the Buku Teks Fizik Tingkatan 4 KSSM.
where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height of the object above the ground.
